Transfered from Linux Config:

Question:

How do I print all arguments submitted on a command line from a bash script?

Answer:

There are couple ways how to print bash arguments from a script. Try some scripts below to name just few.

In this first script example you just print all arguments:

Code:
 #!/bin/bash 
echo $@
If you intend to do something with your arguments within a script you can try somethign simple as the following script:

Code:
 #!/bin/bash 
 for i; do 
    echo $i 
 done
Next we have some script which are doing the same as the previous bash script but employ different approach:

Code:
 #/bin/bash 
 for i in $*; do 
   echo $i 
 done
Let's print all bash arguments using shift:
Code:
 #!/bin/bash 
 
while (( "$#" )); do 
  echo $1 
  shift 
done

Or we can do something obscure like this to print all bash arguments:
Code:
 #/bin/bash 
 
# store arguments in a special array 
args=("$@") 
# get number of elements 
ELEMENTS=${#args[@]} 
 
# echo each element in array  
# for loop 
for (( i=0;i<$ELEMENTS;i++)); do 
    echo ${args[${i}]} 
done